Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
101 views
in Chemistry by (61.1k points)
closed by
One mole of any substance contains `6.022xx10^(23)` atoms/molecules. Number of molecules of `H_(2)SO_(4)` present in 100mL of 0.02M `H_2SO_(4)` solution is
A. `12.044 xx 10^(20)` molecules
B. `6.022 xx 10^(23)` molecules
C. `1 xx 10^(23)` molecules
D. `12.044 xx 10^(23)` molecules

1 Answer

0 votes
by (59.7k points)
selected by
 
Best answer
Correct Answer - A
no of moles `(n) = M xx V` (Litres)
no of molecule `= n xx N_(A)`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...