Calculate the M.F. of a hydrocarbon which caontains `85.7%` carbon and has molecular mass 84

`% C 85. 7` and `%H = 14.3`
This data gives the E.F. of compound to be `CH_(2)` (E.F. mass - 14)
`M.F. = E.F. xx n = CH_(2) xx (84)/(14) = C_(6)H_(12)`

Calculate the M.F. of a hydrocarbon which caontains `85.7%` carbon and has molecular mass 84

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