Question

Resistance and conductivity of a cell containing 0.001 M KCl solution at 298 K are 1500 Ω and 1.46 × 10^-4 S.cm^-1 respectively. What is cell constant.

Answer 1

Given : 

Resistance of KCl solution = 1500 Ω,

conductivity of KCl solution = κ 

= 1.46 × 10^-4S.cm^-1, 

Cell constant = b = ?

Cell constant = Conductivity (k) × Resistance

= 1.46 × 10^-4 × 1500

= 0.219 cm^-1

∴ Cell constant = 0.219 cm^-1