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Solubility of `BaF_(2)` in a solution of `Ba(NO_(3))_(2)`, will be represented by the concentration term:
A. `[Ba^(2+)]`
B. `[F^(-1)]^(2)`
C. `(1)/(2)[F^(-1)]`
D. `2[NO_(3)^(-)]`

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Correct Answer - C
`Ba(NO_(3))_(2)` gives `Ba^(2+)` and `NO_(3)^(-)` ions, hence, concentration of `Ba^(2+)` ion increases. To keep `K_(sp)` constant, `[F^(-)]` decreases.
Thus, it is represented as `(1)/(2)[F^(-)]`

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