C का % `=12/44xx(w_(CO_2))/(W_"यौगिक ")xx100`
`=12/44xx1.32/0.73xx100`=49.32%
H का % =`2/18xx(w_(H_2O))/(W_"यौगिक ")xx100=2/18xx0.6/0.73xx100`=9.13%
`N_2` का भार (w)=`"PVm"/"RT"=(1xx56xx28)/(1000xx0.0821xx273)`=0.0699 ग्राम
N का % =`0.0699/0.365xx100`=19.15%
O का % = 100-[49.32+9.13+19.15]=22.40%