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`27^(@)C` ताप पर 1 `dm^(2)` आयतन वाले फ्लास्क में 8 g डाईऑक्सीजन तथा 4 g डाईहाइड्रोजन के मिश्रण का कुल दाब कितना होगा ?

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`O_(2)` के मोलो की संख्या
`(n_(1)) = (8)/(32) = 0.25`
`H_(2)` के मोली की संख्या `(n_(2)) = (4)/(2) = 2`
मिश्रण में कुल मोलो की संख्या `(n) = n_(1) + n_(2)`
= 0.25 2 = 2.25
गैस समीकरण के अनुसार,
PV = nRT
`R = 0.083 "bar" dm^(3) K^(-1 ) mol^(-1),V = 1dm^(3)`
`T = 27 + 273 = 300 K`
`P xx 1 = 2.25 xx 0.083 xx 300`
`therefore P = 56. 025` bar

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