Question

The reactant which is entirely consumed in reaction is known as limiting reagent. In the reaction `2A+4Brarr3C+4D`, when 5 moles of A react with 6 moles of B, then
(a) which is the limiting reagent?
(b) calculate the amount of C formed?

Answer 1

(i) The given reaction is :
`underset(("2 mol"))(2A)+underset(("4 mol"))(4B)rarrunderset(("3mol"))(3C)+underset(("4 mol"))(4D)`
2 moles of A react with moles of B = 4
5 moles of A react with moles of B = 4
5 moles of A react with moles `B=(("5 mol"))/(("2 mol"))xx4=10 "mol"`
But moles of B actually availble = 6 mol
(i) This means that B is the limiting reagent
(ii) Amount of C formed `= (("3 mol"))/(("4 mol"))xx("6 mol")=4.5 "mol"`.