A liquid which is confined inside an adiabatic piston is suddently taken from state `-1` to state `-2` by a single stage irreversible process. If the piston comes to rest at point 2 as shown, then the enthalpy change for the process will be `:`
A. `DeltaH=(2gammaP_(0)V_(0))/(gamma-1)`
B. `DeltaH=(3gammaP_(0)V_(0))/(gamma-1)`
C. `DeltaH=-P_(0)V_(0)`
D. None of these