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5.3 g of sodium carbonate have been dissolved in 500 mL of the solution. What is the molarity of the solution ?

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Correct Answer - 0.1 M
Molarity of solution (M) `= (("Mass of "Na_(2)CO_(3))/("Molecular mass of "Na_(2)CO_(3)))/("Volume of solution in mL"/(1000))=((5.3g))/(("106 g mol"^(-1))xx("0.5 L"))`
`="0.1 mol L"^(-1)=0.1M`

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