Question

The mass of `CaCO_(3)` produced when carbon dioxide is bubbled through 500 mL of 0.5 M `Ca(OH)_(2)` solution will be :
A. 25 g
B. 50 g
C. 20 g
D. 10 g

Answer 1

Correct Answer - A
Mass of `Ca(OH)_(2)` is calculated as follows :
Molarity `= (("Mass of "Ca(OH)_(2))/("Molecular mass"))/("Volume of solution in litres")`
`0.5=("Mass of "Ca(OH)_(2))/(74)xx(1000)/(500)`
`=0.5xx39 = 18.5g`
`{:(Ca(OH)_(2)+CO_(2),rarr,CaCO_(3)+H_(2)O),(74g,,100g),(18.5g,,(100)/(74)xx18.5=25g):}`.