Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
598 views
in Chemistry by (74.4k points)
closed by
An organic compound is burnt with excess of `O_(2)` to produce `CO_(2)(g)` and `H_(2)O(l)`. Which results in `25%` volume contraction. Which of the following option`(s)` satisfy the given conditins.
A. `10 ml C_(3)H_(8) + 110ml O_(2)`
B. `20ml C_(2)H_(6)O + 80mlO_(2)`
C. `10ml C_(3)H_(6)O_(2) + 50mlO_(2)`
D. `40 ml C_(2)H_(2)O_(4) + 60ml O_(2)`

1 Answer

0 votes
by (74.8k points)
selected by
 
Best answer
Correct Answer - A::C
Check option
(a) `{:(C_(3)H_(8)+5O_(2)(g)rarr3CO_(2)(g)+4H_(2)O(l)),(10" "50" "30):}`
`%` vol. contraction `=(V_(R)-V_(P))/(V_(i)xx100`
`=(60-30)/(120)xx100 = 25%`
(b)`L.R`.
`{:(C_(3)H_(6)O_(2)+(3)/(2)O_(2)rarr3CO_(2)(g)+3H_(2)O(l)),(10mL" "50mL" "30mL):}`
`%` vol. contraction `= (15)/(60)xx100 = 25%`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...