Question

`N_(2)H_(4)`, Hydrazine a rocket fuel can be produced according to the following rection :
`CINH_(2) + 2NH_(3) rarrN_(2)H_(4) + NH_(4)CI`
When `1000 g CINH_(2)` is reacted with excess of `NH_(3),473 g N_(2)H_(4)` is produced. What is the `%` yield of the reaction.

Answer 1

Correct Answer - `76.12%`
`ClNH_(2)+2NH_(3)rarrN_(2)H_(4)+NH_(4)Cl`
`(1000)/(51.5)`mole excess
`=19.417`
`19.417` mole
`%` yield `= (14.781)/(19.417)xx100=76.125%`