Addition of HBr on, `CH-=C-CH_(2)-CH=CH_(2)` and `CH-=C-CH=CH_(2)` separately given:
A. `CH_(3)-=C-CH_(2)-CHBr-CH_(3) and CH_(2)=C-underset(Br)underset(|)(C)H=CH_(2)`
B. `CH_(2)=underset(Br)underset(|)(C)-CH_(2)-CHBr-CH_(3) and CH_(2)=C-underset(Br)underset(|)(C)H=CH_(2)`
C. `CH-=C-CH_(2)-CHBr-CH_(3) and CH-=C-underset(Br)underset(|)(C)H-CH_(3)`
D. both 1 and 2