1 atom of iron will correspond to atomic mass of iron `= 55.84` parts
4 atoms of iron will correspond to mass of iron `= 55.84 xx 4`
`=223.36` parts
Now, `0.335` part of iron will correspond to mass of haemoglobin = 100 parts
`:. 223.36` parts of iron will correspond to mass of haemoglobin `= (100 "parts") xx ((223.36 "parts"))/((0.335 "part"))`
`= 66675` parts
Molecular mass of haemoglobin `= 66675 u`.