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In propylene, `H_(2)C=CH-CH_(3)`, the `C=C-C` bond angle is
A. `120^(@)`
B. `121^(@)`
C. `124^(@)`
D. `126^(@)`

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Correct Answer - C
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In propylene, the `C=C-C` bond angle `(124^(circ))` is larger than the corresponding `C=C-H` bond angle `(121^(circ))` in ethylene because the `CH_(3)` group has more `e^(-)s` than `H` and is, thus, repelled more by the `e^(-)s` of the `C=C` bond.

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