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`64g` of an organic compound contains `24 g ` of carbon, `8gm` of hydrogen and the rest oxygen. The empirical formula of the compound is

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`64g` of an organic compound contains `24 g ` of carbon, `8gm` of hydrogen and the rest oxygen. The empirical formula of the compound is
A. `CH_(2)O`
B. `C_(2)H_(4)O`
C. `CH_(4)O`
D. `C_(2)H_(8)O_(2)`
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Correct Answer - C
`"Elements No. of moles Simpleratio"`
`C(24g)" "24//12=12" "1`
`H(8g)" "8//1=8" "4`
`O (32g)" "32//16=2" "1`
Empirical formula `=CH_(4)O`
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