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An electric current of 100 mA is passed through an electrolyte for 2 hours, 20 minutes and 20 seconds. Find the quantity of electricity passed.

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Given : 

Electric current = I = 100 mA 

= 100 × 10-3A

= 0.1 A 

Time = t = 2 hrs + 20 min + 20 s 

= 2 × 60 × 60 + 20 × 60 + 20 

= 8420 s

The quantity of electricity = Q = ? 

Q = I × t 

= 0.1 × 8420 

= 842 C

∴ Quantity of electricity passed, 

Q = 842 C

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