Correct Answer - A
The addition of `NaOH` converts equivalent amount of acetic acid into sodium acetate. Hence,
Concentration of acetic acid after the addition of
`NaOH=(30)/(70)xx0.2 M`
Concentration of `CH_(3)COONa` after the addition of
`NaOH=(20)/(70)xx0.2 M`
Hence, using the expression
`pH=pK_(a)+log``([Salt])/([Acid])`
`= -log(2xx10^(-5))+log``((20)/(30))`
`=4.699-0.177=4.522`