Question

0.1 g of metal combines with 46.6 mL of oxygen at STP. The equivalent weight of metal is
A. 12
B. 24
C. 18
D. 36

Answer 1

a) 1 mole of `O_(2)` = 4 equivalent of oxygen
22400 mL of `O_(2)` = 4 equivalent of oxygen
46.6 mL of `O_(2)` = (4/22400) xx 46.6 = 0.00832 eq.
Equivalent of metal = Equivalent of oxygen
(Weight)/(Equivalent) = 0.00832
0.1/E = 0.00832 `rARr` E= (0.1)/(0.00832) = 12.0