Question

The `pH` of `Ba(OH)_(2)` solution is `13`. The number millimoles of `Ba(OH)_(2)` present in `10 ml` of solution would be
A. `1.00`
B. `0.50`
C. `10.00`
D. `15.00`

Answer 1

Correct Answer - B
`[OH^(-)]=0.1` and conc. of `Ba(OH)_(2)=(0.1)/(2)`
`:.` The no. of milimoles of `Ba(OH)_(2)` present in `10 ml` soultion `=(0.1)/(2)xx10xx10^(-3)xx10^(3)=0.5`