Question

At `500K` , for an isobaric pracess.
`DeltaS_(system)=-10(KJ)/(molK)` and `DeltaS_(surr)=12(KJ)/(mol K)`
Therefore, `DeltaG` for the entire process is
A. `-500KJ//mol`
B. `-1000KJ//mol`
C. `-600KJ//mol`
D. `-1100KJ//mol`

Answer 1

Correct Answer - D
`DeltaS_("total")=DeltaS_("system")-(DeltaH)/(T)=2KJ//mol`
or `(DeltaH-TDeltaS)/(T)=-2KJ//mol`
or `DeltaH-TDeltaS=-2TKJ//mol=-2xx500KJ//mol`
`=-1000(KJ)/(mol)`