A buffer solution contains `1` mole of `(NH_(4))_(2)SO_(4)` and `1` mole of `NH_(4)OH(K_(b)=10^(-5))`. The `pH` of solution will

Correct Answer - D
`pOH=pK_(b)+log``([Sal t])/([Base])=pK_(b)+log``([Cation])/([Base])`
`[NH_(4)^(+)]=2xx "mole of" (NH_(4))_(2)SO_(4)`
`:. pOH=5+log2=5.3`
or `pH=8.7`

A buffer solution contains `1` mole of `(NH_(4))_(2)SO_(4)` and `1` mole of `NH_(4)OH(K_(b)=10^(-5))`. The `pH` of solution will be:

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