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`pH` of a mixture containing `0.10 M X^(-)` and `0.20 M HX` is: `[pK_(b)(X^(-))=4]`
A. `4+log 2`
B. `4-log 2`
C. `10+log 2`
D. `10-log 2`

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Correct Answer - D
`pOH=pK_(b)+log``([Sal t])/([Acid])=4+log``(0.2)/(0.1)`
` :. pOH=4+log2` and `pH=10-log2`

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