The problem can be discribed as
`? Cm^(3) = 7.6 m^(3)`
By defination, `1 cm = 1xx10^(-2) m`
`:.` The unit factor is `(1cm)/(1xxx10^(-2) m) = 1`
Taking the cube of both the sides we get
`((1cm)/(1xx10^(-2) m))^(3) = 1^(3) = 1`
Multiplying the given volume with the unit factor, we have
`? cm^(3) = (7.6 m^(3)) xx ((1cm^(3))/(1xx10^(-6) m^(3))) = 7.6xx10^(6) m^(3)`
Observation: Note that in curing the unit factor `(1cm//1xx10^(-2) m)`, we cube both the numbers and the units.