Correct Answer - A
Use the relations `1 ft = 12 In`.
`1 "mile" = 5280 ft, 1 "in" = 2.54xx10^(-2) m`, and `1 h = 3600 s`
`"mile" rarr ft rarr "in" rarr m` and `h rarr s`
`(55 ("mile")/(h)) ((580 ft)/(1 "mile")) ((12 "in.")/(1 ft.)) ((2.54xx10^(-2) m)/(1 "in")) ((1h)/(3600 s))`
`= 25 m s^(-1)`