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In the reaction, `4NH_(3)(g)+5O_(2)(g) rarr 4NO(g)+6H_(2)O(g)`, when 1 mole of ammonia and 1 mole of `O_(2)` are made to react to completion
A. (a)1.0 mole of H_(2)O is produced
B. (b)1.0 mole of NO will be produced
C. (c )All the oxygen will be consumed
D. (d)All the ammonia will be consumed

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Correct Answer - C
`4NH_(3(g))+5O_(2(g))rarr 4NO_((g))+ 6H_(2)O_((g))`
`t=0" "1" " 1" "0 " "0`
`t=" "t" "1-4x" " 1-5x" "4x " " 6x`
Oxygen is limiting reagent
So, `X=1/5=0.2` all oxygen consumed
Left `NH_(3)=1-4xx0.2=0.2.`

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