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In the reaction `2Na_(a)S_(2)O_(3)+I_(2) rarr Na_(2)S_(4)O_(6)+ 2NaI`, the equivalent weight of `Na_(2)S_(2)O_(3) (mol. Wt. =M)` is equal to
A. (a)`M`
B. (b)`M//2`
C. (c )`M//3`
D. (d)`M//4`

1 Answer

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Best answer
Correct Answer - A
`Na_(2)overset(+2)(SO_(3))+I_(2) rarr Na_(2)overset(+2.5)(S_(4)O_(6))+NaI`
`n=2xx0.5=1`
`E=M/("n-factor")=M/1=M`

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