Correct Answer - B
Ground-state valence shell electron configuration of `I` is `5s^2 5p^5`. Thus, it has 7 valence electrons, 5 valence `e^(-)s` are used to hold 5 F atoms while 2 valence `e^(-)s` form one lone pair of electrons. Thus, its steric number is `5+1=6`. This implies `sp^3d^2` hybridization, octahedral geometry, and square pyramidal shape (due to one lone pair).
