Question

`DeltaH_(f)^(@)` for `HgO` is `-21.7 kcal//mol` at `25^(@)C`. Calculate the mass of mercury which can be liberated by treatment of excess of `HgO` with `10.0 kcal. At. Wt.` of `Hg=200.6`.

Answer 1

Given `Hg+1//2Orarr HgO, DeltaH^(@)=-21.7kcal`
`:. HgOrarr Hg+1//2O,DeltaH^(@)+21.7kcal,`
`21.7kcal` heat gives `200.6g Hg`
`10.0 kcal `heat gives `(200xx10)/(21.7)=92.44g Hg`