Question

With what velocity should an `alpha ` paricle travel towards the nucleus of a copper atom so as to arrive at a distance `10^(-13)m` from the nucleus of the copper atom?

Answer 1

At closet distance, kinetic energy should be equal to repulsion energy.
`(1)/(92)mu^(2) = (1)/(4pi) epsilon_(0) xx (2Z e^(2))/(r)`
where repuslion energy.
`(q_(1) q_(2))/(r) = (2e.Z.e)/(r) = (2Ze^(2))/(r)`
`:. U^(2) = (Ze^(2))/(pi epsilon_(0)mr)`
`= (29xx(1.6xx10^(-19))^(2))/(3.14xx8.85xx10^(-12)xx(4xx1.672xx10^(-27))xx10^(-13))`
`= 6.3xx10^(6)m sec^(-1)`