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Consider the following process of decay,
`._(92)^(234)U rarr ._(90)^(230)Th + ._(2)^(4)He, t_(1//2) = 250000 yr`
`._(90)^(230)Th rarr ._(88)^(226)Ra + ._(2)(4)He, r_(1//2) = 80000 yr`
`._(88)^(226)Ra rarr ._(86)^(222)Rn + ._(2)^(4)He, t_(1//2) = 1600 yr`
After the above process has occurred for a long tiem, a state is reached where for every two thorium atoms formed form `._(92)^(234)U` one decomposes to from `._(88)^(226)Ra` and for every two `._(88)^(226)Ra` formed, one decomposes. The ratio of `._(90)^(230)Th` to `._(88)^(226)Ra` will be:
A. `(25000)/(80000)`
B. `(80000)/(1600)`
C. `(250000)/(1600)`
D. `(250000xx1600)/(80000)`

1 Answer

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Best answer
Correct Answer - `(b)`
Follow radioactive equillibrium.
`(N_(A))/(N_(B)) = (t_((1//2)A))/ (t_((1//2)B))`

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