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Find the equivalent resistance between the terminals F and B in the network shown in the figure below given that the resistance of each resistor is 10 ohm.

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Applying Kirchhoff’s voltage law to loop FGHF, we get,

– 10I1 – 10(I1 – I2) + 10(I – I1) + 10(I – I1) = 0

∴ – 10I1 – 10I1+ 10I2 + 10I – 10I1 + 10I – 10I1 = 0

∴ 201 – 40I1 + 10I2 = 0 

∴ 2I – 4I1 + I2 = 0 …… (1)

Applying Kirchhoff’s voltage law to loop GABHG, we get,

– 10I2 – 10I2 + 10(I – I2) + 10(I1 – I2) = 0

∴ – 20I2 + 10I – 10I2 + 10I1 – 10I2 = 0

∴ 10I + 10I1 – 40I2 = 0 .

∴ I + I1 – 4I2 = 0 …… (2)

Applying Kirchhoff’s voltage law to loop EFHBCDE, we get,

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