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एक कण X - अक्ष के अनुदिश x = 0 से x = 5 मीटर तक परिवर्ती बल `F=7-2x+3x^(2)` न्यूटन के अंतर्गत चलता है। इस प्रक्रम में किया गया कार्य है:
A. 70 जूल
B. 270 जूल
C. 35 जूल
D. 135 जूल |

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Correct Answer - D
`W=int_(0)^(5)Fdx=int_(0)^(5)(7-2x+3x^(2))dx`
`=[7x-x^(2)+x^(3)]_(0)^(5)=135` जूल |

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