Question

An ionic compound contains 29.08% sodium, 40.56% sulphur and 30.36% oxygen by mass. What is the formular of the sulphur-containing anion in the compound?
A. `S_(2)O_(3)`^(2-)
B. `S_(2)O_(4)^(2-)`
C. `S_(2)O_(5)^(2-)`
D. `S_(2)O_(6)^(2-)`

Answer 1

Correct Answer - A

Answer 2

mass of Na : mass of S : mass of O₂ == 29.08 : 40.56 : 30.36
atm no of Na : atm no of S : atm no of O₂ == 2 : 2 : 3
therefore empr formula is Na₂S₂O₃
splitting that - we will get S₂O₃^2-