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0.16 g of dibasic acid required 25 ml of decinormal NaOH solution for complete neutralisation. The molecular weight of the acid will be
A. 45
B. 90
C. 64
D. 128

1 Answer

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Correct Answer - D
2.5 m mol `NaOH rArr 1.25` m mol dibasic acid reqd.
`1.25xx10^(-3) mol =0.16 g`
`1 mol =0.16/(1.25xx10^(-3)) g =128 g `

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