Correct Answer - B
Transition metl oxide with highest oxidation states is most acidic in character because of the very less difference in the values of electronegativity between `Mn^(7+) and O^(2-)`, and the decreasing order of acidic character is `overset(+7)(Mn_(2))O_(7) gt overset(+4)(Mn)O_(2) gt overset(+3)(Mn_(2))O_(3) gt overset(+2)(Mn)O`.
