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`C_(3)H_(8)Ooverset(O)underset(K_(2)Cr_(2)"O"//H)rarrC_(3)H_(6)Ooverset(I_(2))underset(NaOH)rarrCHI_(3)`
The starting compound is
A. `CH_(3)CH_(2)CH_(2)OH`
B. `CH_(3)underset(OH)underset(|) CH-CH_(3)`
C. `CH_(3)-O-CH_(2)-CH_(3)`
D. `CH_(3)CH_(2)CHO`

1 Answer

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Best answer
Correct Answer - 2
`CH_(3)-underset(OH)underset(|)CH-CH_(3)overset([O])underset(K_(2)Cr_(2)O_(7)+H_(2)SO_(4))to C_(3)H_(6)Ooverset(I_(2).alk)underset(warm)toCHI_(3)`

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