Question

0.49 gm of chloroplatinate of a diacidic base gave on ingintion 0.195 gm of platinum. Calculate the molecular mass of the base.

Answer 1

`("Mol. Mass of chloroplatinate")/("At. Mass of platinum") = ("Mass of chloroplatinate taken")/("Mass of platinum left")`
`= (0.49)/(0.195)`
Let B be the equivalent mass of the base.
`(2B +410)/(195) = (0.49)/(0.195)`
or `2B =[(0.49)/(0.195) xx 195 - 410] = 80`
or `B = 40`
Mol. mass of the base = Eq. mass `xx` Acidity `= 40 xx 2 = 80`