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1.575 gm of an organic acid was dissolved in 250 ml of water Further, 20 ml of this solution required 16 ml of `(N)/(8)` alkali solution for complete neutralisation. If the basicity of the acid is 2, find its molecular mass.

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`16L N//8` alkali solution `-=20mL` of acid solution
`2mL 1N` alkali solution `-=20mL` of acid solution
`(2 xx250)/(20)mL 1N` alkali solution `-=250mL` of acid solution
`25mL 1N` alkali solution `-=1.575g` acid
`1000mL 1N` alkali solution `-= (1.575)/(25) xx 1000g` acid
Eq. mass of the acid `= 63g` acid
Mol. mass of the acid `= 63 xx 2 = 126`

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