Question

Calculate the molal depression constant of a solvent which has freezing point `16.6^(@)C` and latent heat of fusion `180.75 "J g"^(-1)` :
A. 2.68
B. 3.86
C. 4.68
D. 2.86

Answer 1

Correct Answer - B
`K_(f)=(RT_(0)^(2))/(1000L)" "T_(0)=273+16.6=289.6K`
`=(8.314xx(289.6)^(2))/(1000xx180.75)=3.86`]