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Number of moles of `K_(2)Cr_(2)O_(7)` can be reduced by 1 mole of `Sn^(2+)` ions is:
A. `(1)/(3)`
B. `(3)/(2)`
C. `(5)/(2)`
D. `(6)/(5)`

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Best answer
Correct Answer - A
Balanced equation is:
`Cr_(2)O_(7)^(2+)+14H^(+)+3Sn^(2+) to 2CrO_(7)^(2-)`
1 mole of `Sn^(2+) -=(1)/(3)"mole of" Cr_(2)O_(7)^(2-)`

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