Question

Calculate the pressure exerted by `10^(23)` gas molecules each of mass `10^(-22) g` in a container of volume 1 litre the rms speed is `10^(5) cm s^(-1)`

Answer 1

Using kinetic gas equation,
`P = (1)/(3) (mnc^(2))/(V)`
Given, `V = 1` litre `= 1000 mL = 1000 cm^(3), n = 10^(23), m = 10^(-22) g " and " c = 10^(5) cm s^(-1)`
Substituting the values in the above equation,
`P = (1)/(3) xx (10^(-22) xx 10^(23) xx 10^(10))/(1000) = 3.33 xx 10^(7) " dyne" cm^(-2)`