Question

The time taken for effusion of 64 mL of oxygen will be as the time taken for the effusion of which of the following gases under identical conditions ?
A. `64 mL " of " H_(2)`
B. `100 mL " of " N_(2)`
C. `64 mL " of " CO_(2)`
D. `45.24 mL" of " SO_(2)`

Answer 1

Correct Answer - D
`(r_(O_(2)))/(r_("gas")) = sqrt((M_("gas"))/(M_(O_(2))))`
`(64)/(V) = sqrt((64)/(32)) " or " V = (64)/(sqrt2) = 45.25 mL`