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Two perfect monoatomic gases at absolute temperature `T_(1)` and `T_(2)` are mixed. There is no loss of energy. Find the temperature of the mixture if the number of moles in the gases are` n_(1)` and `n_(2)`.

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Correct Answer - `T = (n_(1) T_(1) + n_(2) T_(2))/(n_(1) + n_(2))`
Let final temperature is T
`(3)/(2) n_(1) RT_(1) + (3)/(2) n_(2) RT_(2) = (3)/(2) (n_(1) + n_(2)) RT`
`T = (n_(1) T_(1) + n_(2) T_(2))/(n_(1) + n_(2))`

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