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56 g of nitrogen and 96 g of oxygen are mixed isothermally at a total pressure of 10 atm. The partial pressures of oxygen and nitrogen (in atm) are respectively:
A. 4, 6
B. 5, 5
C. 2, 8
D. 8, 2

1 Answer

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Correct Answer - A
`n_(N_(2)) = (56)/(28) = 2 , n_(O_(2)) = (96)/(32) = 3`
`P_(N_(2)) = x_(N_(2)) xx P_("Total")`
`= (2)/(2 + 3) xx 10 = 4 atm`
`P_(O_(2)) = 10 - 4 = 6 atm`

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