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At `20^(@)C`, the `Ag^(+)` ion concentration in a saturated solution `Ag_(2)CrO_(4)` is `1.5 x10^(-4)` mol `//` litre. At `20^(@)C`, the solubility product of `Ag_(2)CrO_(4)` would be
A. `1.687xx10^(-12)`
B. `1.75xx10^(-10)`
C. `3.0xx10^(-8)`
D. `4.5xx10^(-10)`

1 Answer

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Best answer
Correct Answer - A
`Ag_(2)CrO_(4)hArr2Ag^(+)+CrO_(4)^(2-)`
`Ag^(+)=1.5xx10^(-4)M`
`CrO_(4)^(2-)=0.75xx10^(-4)M((1)/(2)" of "Ag^(+))`
`K_(sp)=(1.5xx10^(-4))xx(0.75xx10^(-4))=1.687xx10^(-12)`

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