प्रश्नानुसार
`E_(2)=-5.42xx10^(-12)ergs`
`E_(3)=-2.41xx10^(-12)ergs`
`h=6.62 xx10^(27)ergs s`
अब `because DeltaE=E_(3)-E_(2)`
`=(-2.41xx10^(-12)+5.42xx10"^(-12))ergs`
`=+3.01xx10^(-12)ergs`
या, `hv=3.01xx10^(-12)ergs`
+2 रसायन भाग 1
या, `(hc)/(lamda)=3.01xx10^(-12)ergs`
या, `lamda=(hc)/(3.01xx10^(-12))`
`=((6.62xx10^(-27)ergs s)xx(3xx10^(10)cm s^(-1)))/(3.01xx10^(-12)ergs )`
`=6.604xx10^(-5)cm`
`=6604 xx10^(-8)cm =6604Å.`