`K_(p) = K_(c) + (RT)^(Deltax)`
या `K_(c) = (K_(p))/((RT)^(Deltax))`
प्रश्नानुसार , `T = 273 + 20 = 293 K`
`R= 0.0821 L-atm K^(-) mol^(-1)`
`Deltax = 2 - (2 + 1) = - 1`
`K_(p) = 1.9xx 10^(3) atm^(-)`
`:. K_(c) = (1.9 xx 10^(3))/((0.0821 xx 293)^(-1))`
`= 1.9 xx 10^(3) xx (0.0821 xx 293)`
` = 4.57 xx 10^(4)`.