we have an elliptical orbit and let maximum and minimum distance is A and A’ and let S be the sun on the orbit.

we have SA = 152 x 106 km
we have SA’ = 94.5 x 106 km
Another focus point is S’
The distance between S’ and S be C
So SA = a + c = 152 x 106 km .......(1)
focus a – c = 94.5 x 106 km.....(2)
We need to find the distance from the sun to the other focus.
Subtracting (1) and (2) we have
a + c – (a – c) = 152 x 106 – 94.5 x 106
a + c – a + c = 57.5 x 106 km
So 2c will be the distance from sun to the other focus and it is 57.5 x 106 km