Question

The ground state electronic configuration of S is `3s^(2) 3 p^(4)` . How does it form the compound `SF_(6)` ?
A. Due to octahedral shape of S atoms
B. Due to presence of vacant 3d- orbitals which provide 6 unpaired electrons in excited state
C. Due to `sp^(3)` hybridisation of S atom which provides 6 electrons to 6 F atoms
D. Due to presence of 3 sigma and 3 pi bonds between S and F

Answer 1

Correct Answer - B
S can go into excited state with 6 unpaired electrons due to presence of vacant 3d - orbitals, which are overlapped by six F electrons.
Ground state

Excited state